-2x^2+4x-3=-x^2+2x-2

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Solution for -2x^2+4x-3=-x^2+2x-2 equation: 



-2x^2+4x-3=-x^2+2x-2

We move all terms to the left:

-2x^2+4x-3-(-x^2+2x-2)=0

We get rid of parentheses

-2x^2+x^2-2x+4x+2-3=0

We add all the numbers together, and all the variables

-1x^2+2x-1=0

a = -1; b = 2; c = -1;
Δ = b2-4ac
Δ = 22-4·(-1)·(-1)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-2}{-2}=1$

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